On the Recursive Sequence Xn+1 = Xn-7/1+xn-1xn-3xn-5

Abstract

In this paper we are going to analyze the following difference equation x(n+1) = x(n-7)/1+x(n-1)x(n-3)x(n-5) n = 0, 1, 2,..., where x-7, x-6, x-5, x-4, x-3, x-2, x-1, x(0) is an element of (0, infinity).